Find the integral: dx/(cosx+sinx)^(1/2)
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[Post New] 22 Feb 2012 16:44:56 IST
   Subject: Find the integral: dx/(cosx+sinx)^(1/2)
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Niladri Chakraborty (155)


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Find the integral: dx/(cosx+sinx)^(1/2)
NiladriRanjitKumarChakraborty
    
[Post New] 22 Feb 2012 17:44:11 IST
   Subject: Find the integral: dx/(cosx+sinx)^(1/2)
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mohamed arafath (20)


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put t^2=cosx+sinxcosx-sinx=2tdt/dxso que 2dt/(cosx-sinx) sin2x=t^4-1(cosx-sinx)^2=1-sin2xcosx-sinx=1-{t^4-1}cosx-sinx=2-t^4so que 2dt{/2-t^4}i hope after u can do this
 
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[Post New] 23 Feb 2012 06:23:48 IST
   Subject: Find the integral: dx/(cosx+sinx)^(1/2)
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Niladri Chakraborty (155)


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mohamed, would you please be more clear. im not understanding the solution. kindly post the solution again.
 
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[Post New] 23 Feb 2012 09:58:44 IST
   Subject: Find the integral: dx/(cosx+sinx)^(1/2)
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mohamed arafath (20)


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put t^2=(cosx+sinx)             (cosx-sinx)=2tdt/dx              sin2x=t^4-1         (cosx-sinx)^2=1-sin2x                                    cosx-sinx={2-t^4}^1/2     dx/(cosx+sinx)^1/2 = 2dt/{2-t^4}^1/2 i hope after u can solve this
 
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[Post New] 24 Feb 2012 10:14:03 IST
   Subject: Find the integral: dx/(cosx+sinx)^(1/2)
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mohamed arafath (20)


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good question
 
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