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Community Discussion Question:
Cos 1 Cos2 Cos3............Cos179
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Forum Index -> Trignometry |
originally posted here on IIT-JEE / AIEEE community
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cos1.cos2.cos3...............cos179???? plss reply fast | |||||||||||||
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We could use the formula:
cos(180-k)=-cos k
-cos 179 = cos (180-179)=cos 1.......
-cos 178 = cos (180-178)=cos 2 and so on....
We'll re-write the sum substituting the first terms, till cos 89, by their equivalents and we'll get:
-cos 179 -cos 178 -cos 177 - ... +cos 90 +...+cos 177 + cos 178 + cos 179.
Reducing the similar terms, we'll obtain:
S=0 |
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we don t need anything just see s=cos1 cos2 cos3.......................cos179 but look now s=cos1 cos2 cos3.............cos90..........cos179 as cos90=0 so s=0 |
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0because cos90=0 and it will come between the series | |||||||||||||
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it will be 0 bec cos 90 in between is o |
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0 bec cos 90 is 0 |
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its 0......as cos90=0.
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Forum Index -> Trignometry | |
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